Answer:
Step-by-step explanation:
we know that
The area of a circle is equal to
In this problem we have
Substitute and find the area
Remember that
subtends the area of complete circle
so
by proportion
Find the area of the shaded regions
The central angle of the shaded regions is equal to 
U turn negative numbers from mixed numbers to improper fractions the same way u do with positive...u just temporarily disregard the negative sign.
Example :
- 2 2/3.....temporarily disregard the negative sign......take ur whole number (2) and multiply it by ur denominator (3) giving u 6, then add that to ur numerator (2) giving u 8....then put that number over the original denominator (3) giving u 8/3...and then put back ur negative sign...-8/3
Answer:
9, 32 and 36
Step-by-step explanation:
The perimeter of a triangle is the sum of all the sides. Since you know the perimeter and the expressions for each of the sides, you can set up an equation to solve for the variable and find the values of the other sides:
one side: '4 times the shortest side' = 4s
shortest side: 's'
third side: '23 more than the shortest side' = s + 23
perimeter = 77
Equation: 4s + s + (s + 23) = 77
Combine like terms: 6s + 23 = 77
Subtract 23 from both sides: 6s + 23 - 23 = 77 - 23 or 6s = 54
Divide by 6: 6s/6 = 54/6 or s = 9
one side: 4s = 4(9) = 36
shortest side: s = 9
third side: s + 23 = 9 + 23 = 32
I’m sorru but there’s nothing there
Answer:
m∠KIJ = m∠LIM ⇒ answer B
Step-by-step explanation:
* Lets explain how to solve the problem
∵ I is the mid-point of NH
∴ IN = IH
- MJ is perpendicular to NH and passes through I the mid-point of NH
∴ MJ is perpendicular bisector of NH
- NH ⊥ MJ and intersects it at I
∴ m∠NIM = m∠NIJ = 90°
- ∠ NIM consists of two angles ∠NIL and ∠MIL
∵ m∠NIM = m∠NIL + m∠MIL
- ∠NIJ consists of two angles ∠NIK and ∠JIK
∵ m∠NIJ = m∠NIK + m∠JIK
∴ m∠NIL + m∠MIL = m∠NIK + m∠JIK ⇒ (1)
∵ NH bisects ∠KIL
∴ m∠NIL = m∠NIK ⇒ (2)
- From (1) and (2)
∴ m∠MIL = m∠JIK
* m∠KIJ = m∠LIM
