X^2-x-12 in (x+p)(x+q) form

Mathematics

2 answers:

SpyIntel [72]3 years ago

7 0

$x^2-x-12=x^2-4x+3x-12=x(x-4)+3(x-4)\\\\=(x-4)(x+3)=[x+(-4)](x+3)$

DochEvi [55]3 years ago

5 0

X^2-x-12 = (x - 4)(x + 3)

Hope that helps.

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Hal and Renee play the following game a bag has 11 tiles in it each with a letter from the word probably in it Hal and Renee tak

Masteriza [31]

Answer:

<em>D. The game is not fair because the probability of Hal drawing a winning letter is less then the probability of Renee drawing a winning letter </em>

Explanation:

The word is not probably, which has 8 letters, but probability, which has 11 letters

<u>1. Hal</u>

Probability of drawing a vowel

The vowels are: o, a, i, i, and y: 5

The total number of letters in the bag is 11.

Probability of vowel = 5 / 11

<u>2. Renee</u>

Probability of drawing a consonant

The consonants are: p, r, b, b, l, t, and y: 7

Probability of a drawing a consonant: 7 /11

<h2>Conclusion</h2>

As you see, the probability of drawing a vowel (5/11), which is the winning letter for Hal, is less than the probability of drawing a consonant (7/11), which is the winning letter of Renee. Then,