Another triple integral. We're integrating over the interior of the sphere
Let's do the outer integral over z. z stays within the sphere so it goes from -2 to 2.
For the middle integral we have
x is the inner integral so at this point we conservatively say its zero. That means y goes from 
and 
Similarly the inner integral x goes between 
So we rewrite the integral
Let's work on the inner one,
There's no z in the integrand, so we treat it as a constant.
So the middle integral is
I gotta go so I'll stop here, sorry.
The pong will be at 3.5 m
Answer:
P(x)=(x-2)(x-4)(x+3)(x+6)
Step-by-step explanation:
Given: P(x)=x⁴+3x³-28x²-36x+144
It is a polynomial with degree 4.
It should maximum four factor.
Hit and trial error method.
Put x = 2 into P(x)
P(2)=2⁴+3×2³-28×2²-36×2+144
P(2) = 0
So, x-2 would be factor of P(x)
Now divide x⁴+3x³-28x²-36x+144 by x-2 to get another factors
Put x = 4
now divide 
by x-4
Now factor 
Complete factor of P(x)
P(x)=(x-2)(x-4)(x+3)(x+6)
It’s definitely not D or A but the closest one would be C, that’s what I would put. So the answer might be C.90
3 times 36= 108
2 times 24= 48
108+48= 156
156-8=148 rolls
