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puteri [66]
3 years ago
10

The ans to 3/4+2/3 when using a common denominator to add unlike fractions

Mathematics
1 answer:
pychu [463]3 years ago
5 0

Answer:

17/12 = 1 5/12

Step-by-step explanation:

The common denominator of 4 and 3 is 12.

The equivalent fraction of 3/4 is 9/12.

The equivalent fraction of 2/3 is 8/12.

Their total is 17/12 (or 1 5/12).

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In three to five sentences, explain the importance of sentence structures in good writing.
jenyasd209 [6]

Answer:

Sentence structure needs to simple, standalone, Grammarly justified and able enough to convey the writer thoughts and feelings clearly

Step-by-step explanation:

Sentence structure is very essential to convey the idea of the writer clearly. It is just like the skeleton of a write up and hence its framework needs to be clear and able enough to express the real sense. The structure of sentence needs to be complete with adequate grammar and punctuations. A good sentence must be able to express a complete idea  on its own.

4 0
3 years ago
Can someone plzzz hekppp meeee
erastova [34]

Answer:

Use this formula for these kinda things.

Step-by-step explanation:

Remember The z is the hypathonous, it means the biggest side.

{a}^{2}  +  {b}^{2}  =  {c}^{2}

where Z is going to be C

put this all together

{7}^{2}  +  {18}^{2}  =  {z}^{2}

put it into calculator, means 373=

{z}^{2}

therfore take the square root, it will be

z =  \sqrt{373}

which it will be 19.31

5 0
3 years ago
Tyler bought a shirt from the 25% off rack. It normally costs $16. Here is the money he paid. A ten dollar bill and two one doll
Arturiano [62]
If you take 25% off of 16 you would pay $12(75% left to pay).
8 0
2 years ago
Solve for the following y: -6x +2y=8
frosja888 [35]
-4/3+1/3y I hope thats right 
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=z%5E%7B7%7D%3D128i" id="TexFormula1" title="z^{7}=128i" alt="z^{7}=128i" align="absmiddle" cla
abruzzese [7]

If <em>z</em> ⁷ = 128<em>i</em>, then there are 7 complex numbers <em>z</em> that satisfy this equation.

z^7 = 128i = 2^7i = 2^7e^{i\frac\pi2}

\implies z=\sqrt[7]{2^7} e^{i\frac17\left(\frac\pi2+2n\pi\right)}

(where <em>n</em> = 0, 1, 2, …, 6)

\implies z = 2 e^{i\left(\frac\pi{14}+\frac{2n\pi}7\right)}

\displaystyle\implies z = 2 \left(\cos\left(\frac\pi{14}+\frac{2n\pi}7\right)+i\sin\left(\frac\pi{14}+\frac{2n\pi}7\right)\right)

3 0
2 years ago
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