Never. If they are not on the same plane, then they cannot intersect because 2 lines and 1 point are always on a plane, in this case the original line, then a point in the middle to the point that creates the other line would be included, hence if they are non-coplaner then they cannot intersect.
Answer: Choice B
There is not convincing evidence because the interval contains 0.
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Explanation:
The confidence interval is (-0.29, 0.09)
This is the same as writing -0.29 < p1-p1 < 0.09
The thing we're trying to estimate (p1-p2) is between -0.29 and 0.09
Because 0 is in this interval, it is possible that p1-p1 = 0 which leads to p1 = p2.
Therefore, it is possible that the population proportions are the same.
The question asks " is there convincing evidence of a difference in the true proportions", so the answer to this is "no, there isn't convincing evidence". We would need both endpoints of the confidence interval to either be positive together, or be negative together, for us to have convincing evidence that the population proportions are different.
Answer:
24ab-8ac
Step-by-step explanation:
Assuming you want to simplify it.
Original equation: 8a(3b+6c-7c)
Apply 8a to each variable in the paranthesis: (8a)(3b)+(8a)(6c)+(8a)(-7c)
After multiplication: 24ab+48ac-56ac
Combine like terms: 24ab-8ac
Answer:
34 degrees.
Step-by-step explanation:
Assuming AK is a straight line and being shown angle JDK is right and 90 degrees it can be stated that 4x + (3x-8) = 90 degrees.
Drop the parentheses and get 7x - 8 = 90.
Add 8 to both sides 7x = 98.
Divide both sides by 7, x = 14.
Plug that x value into (3x-8), [3(14)-8] = 34 degrees.
Hi there!
Reflections across the line y = -x always go by the rule (-y, -x). We can use this rule to get our answer here. We are given the aftermath of the reflection coordinates, which are <span>A'(-1, 1), B'(-2, -1), and C'(-1, 0). All we have to do now is switch up the coordinate values and multiply them by -1. Here is the work -
A'(-1, 1) => (1, -1) => x -1 => A(-1, 1)
B'(-2, -1) => (-1, -2) => x -1 => B(1, 2)
C'(-1, 0) => (0, -1) => x -1 => C(0, 1)
Therefore, the coordinates of Triangle ABC are A(-1, 1); B(1, 2); C(0,1). Hope this helped and have a phenomenal day!</span>
