Since TSQ and QSR are supplementary, they give 180 when summed. TSQ is 150, so QSR must be 30.
Therefore, you have

The expression for the greatest common factor of 20 and 30 using the distributive property is 10(2 + 3)
Pounds of ice = 20
Number of cups = 30
The relation for the distributive property :
a × (b + c)
Expand ;
a × (b + c) = (a × b) + (a × c) = ab + ac
Finding the greatest common factor of 20 and 30 ;
(2 × 10) + (3 × 10)
According to the distributive property
(2 × 10) + (3 × 10) = 10(2 + 3)
Therefore, the expression for the greatest common factor is 10(2 + 3)
Learn more :brainly.com/question/15263211
If

represent a family of surfaces for different values of the constant

. The gradient of the function

defined as

is a vector normal to the surface

.
Given <span>the paraboloid

.
We can rewrite it as a scalar value function f as follows:

The normal to the </span><span>paraboloid at any point is given by:

Also, the normal to the given plane

is given by:

Equating the two normal vectors, we have:
</span>

Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid
such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
Answer:
12 or 12.1752499
Step-by-step explanation:
Answer:
Answer is 628 cm^3
Step-by-step explanation:
using base area lets find radius
base area=pie*(r)^2
78.50=3.14*r^2
78.50/3.14=r^2
25=r^2
5=r
now using lateral area lets find height
lateral area=2*pie*r*h
251.20=2*3.14*5*h
251.20=31.4*h
251.20/31.4=h
8=h
volume of cylinder=pie*(r)^2*h
=3.14*(5)^2*8
3.14*25*8
=628 cm^3