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3 years ago

45 units and is centered at

Mathematics

1 answer:

mariarad [96]3 years ago

3 0

The correct question is:

A circle has a radius of 45 units and is centered at (-2.4, -4.8).

What is the equation of this circle?

Answer:

Equation of the circle is;

(x + 2.4)² + (y + 4.8)² = 2304

Step-by-step explanation:

The standard equation of a circle is;

(x - a)² + (y - b)² = r²

where;

(a,b) is the center of the circle and r is the radius of the circle

Now, from the question, the circle is centered at (-2.4, -4.8) and the radius is 45

Thus, plugging those values into the standard form of equation of a circle, we have;

(x - (-2.4))² + (y - (-4.8))² = 48²

This gives;

(x + 2.4)² + (y + 4.8)² = 2304

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Read 2 more answers

Monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 4,000,000 and a mean

In-s [12.5K]

Using the normal distribution, it is found that there is a 0.2776 = 27.76% probability that the life span of the monitor will be more than 20,179 hours.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 19000, \sigma = \sqrt{4000000} = 2000$

The probability that the life span of the monitor will be more than 20,179 hours is <u>one subtracted by the p-value of Z when X = 20179</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20179 - 19000}{2000}$

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More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago

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Sladkaya [172]

<h3><u>Answer:</u></h3>

$\boxed{\boxed{\pink{\sf Option \ A \ is \ correct .}}}$

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$\bf \implies g(x) = x^2 - 9 \\\\\bf\implies g(x) = x^2-3^2\\\\\bf\implies \boxed{\red{\bf g(x) = (x+3)(x-3) }}\:\:\bigg\lgroup \blue{\tt Using \ (a+b)(a-b) \ = a^2-b^2 }\bigg\rgroup$

I have also attached the graph of x²-9.

<h3><u>Hence </u><u>option</u><u> </u><u>A</u><u> </u><u>is</u><u> </u><u>corr</u><u>ect</u><u> </u><u>.</u></h3>

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