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shutvik [7]
3 years ago
14

I need help plss guys like right now

Mathematics
1 answer:
Dominik [7]3 years ago
4 0

Answer:

r^-8s^-5 = 1/r^8 * s^5 = s^5/r^8

s^5/r^8 = r^-8s^5

Owen forgot put s^5 in the denominator to make its exponent negative.

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4 0
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Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
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</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
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8 0
3 years ago
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