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alexandr402 [8]
3 years ago
5

Someone help me answer these 3 questions because they are due by 5:00 today plz questions 12-14

Mathematics
1 answer:
Zanzabum3 years ago
3 0

13). z = ( 9/13)(C)

Solve for C:

Step 1: flip Equation:

9/13 c = z

Step 2: Divide both sides by 9/13

9/13 c/9/13 = z/9/13

C = 13z/9

Answer: Letter Choice, (D), C = 13z/9

12.). Let " h" be the number of hikes:

Expense of First Club:

C * h = 20 + 5h

Expense of Second CluB:

C * h = 7h

20 + 5h < 7h

20 < 2h

h > 10 hikes

Answer: The First Club is Less Expensive, If it is more than Ten Hikes.

14.). Co-Efficient of Friction Formula:

ma = F - mw

+ mw + mw (cancel out +mw)

Mw + ma = F - ma

-ma -ma (Cancel out -ma)

Divide: Both sides by w:

Mw/w = F - ma/w

Therefore, Answer: Letter Choice, (D), M = F - ma/w

Hope that helps!!!! Have a wonderful day!!!! : )

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3 years ago
Winston owns a coffe cart. He charges $1.50 for a cup of coffe , and it costs him $0.50 to make each cup of coffe plus $100 a da
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100 + 0.50c = 1.50c <== ur equation
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Megan's text messaging plan costs $5 for the first 700 messages and 30¢ for each additional text message. If she owes $63.20 for
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Answer:

Fixed cost $14 -350 messages

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Step-by-step explanation:

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3 years ago
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The monthly output P of a light bulb factory is given by the formula P = 450LK, where L is the amount invested in labor and K th
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Answer:

C(p)  = 4,96 (in thousands of dollars)

l = 2980 $  invest in labor

k = 2980 $ invest in equipment

Step-by-step explanation:

Information we have:

Monthly output   P = 450*l*k       ⇒  k = P/450*l

But the production need to be 4000

Then k = 4000/450*l

Cost of production = l * k     (in thousands of dollars)

C(l)  =  l  + 4000/450*l

Taking derivatives (both members of the equation)

C´(l) = 1 - 400 /45*l²          ⇒ C´(l) = 0          ⇒ 1 - 400/45l²  = 0

45*l² -  400  = 0              ⇒  l²  = 400/45

l = 2.98 (in thousands of dollars)

l = 2980 $ And

k = 400/45*l           ⇒  k 400/45*2.98

k = 2.98  (in thousands of dollars)

C(p) = l + k

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C(p)  = 5960 $

4 0
3 years ago
If a cannonball is shot directly upward with a velocity of 160 ft per​ second, its height above the ground after t seconds is gi
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Step-by-step explanation:

If a cannonball is shot directly upward with a velocity of 160 ft per​ second. Its height as a function of time is given by :

h(t)=160t-16t^2 .......(1)

t is in seconds

(a) Velocity is given by :

v=\dfrac{dh}{dt}\\\\v=\dfrac{d(160t-16t^2)}{dt}\\\\v=(160-32t)\ ft/s  

Acceleration is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(160-32t)}{dt}\\\\a=-32\ ft/s^2

(b) For maximum height put \dfrac{dh}{dt}=0

i.e.

160-32t=0\\\\t=5\ s

Put t = 5 s in equation (1). So,

h(5)=160t-16t^2\\\\h(5)=160(5)-16(5)^2\\\\h(5)=400\ ft

(c) When the ball reaches ground, its height is equal to 0. So,

h(t) = 0

160t-16t^2=0\\\\t(160-16t)=0\\\\t=0,t=10\ s

Hence, this is the required solution.

4 0
3 years ago
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