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Yuki888 [10]
3 years ago
5

Write a number sentence that equals 4/6​

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

when you have a function that is 4/6 think of it as reversed the number its going to be 4/6=6×4.

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Consider the function below. (If an answer does not exist, enter DNE.) g(x) = 190 + 8x3 + x4 (a) Find the interval of increase.
galben [10]

Answer:

The interval of increase of g(x) is (-6,+\infty).

Step-by-step explanation:

The interval of increase occurs when first derivative of given function brings positive values. Let be g(x) = 190 + 8 \cdot x^{3} + x^{4}, the first derivative of the function is:

g'(x) = 24 \cdot x ^{2} + 4\cdot x^{3}

g'(x) = 4 \cdot x^{2}\cdot (6+x)

The following condition must be met to define the interval of increase:

4\cdot x^{2} \cdot (x+6) > 0

The first term is always position due to the quadratic form, the second one is a first order polynomial and it is known that positive value is a product of two positive or negative values. Then, the second form must satisfy this:

x + 6 > 0

The solution to this inequation is:

x > - 6

Now, the solution to this expression in interval notation is: (-6,+\infty)

3 0
3 years ago
How to multiply 18 3/8 x 1/4
user100 [1]
Decimal Form: 
4.59375<span> 
</span>
Exact Form:     
<span>147/32</span><span> 

</span>Mixed Number Form: <span>4 19/32</span>
4 0
3 years ago
A department store uses a markup of 40%. Calculate the selling price of a shirt that cost the retailer $25.
drek231 [11]
The answer is a. $35. First you multiply 25 by .40. Then you add the product to 25.
8 0
3 years ago
Whoever gets this in 5 mins will be brainlest
ivanzaharov [21]

Answer:

easy its c

Step-by-step explanation:

so you do you start with the left 2 to the third power is 8

then the right side now is -3 to the second power is -9

in total 8- (9-)

so your answer is -1

hope this helps

8 0
2 years ago
Read 2 more answers
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
3 years ago
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