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Komok [63]
4 years ago
14

Let f(x) = 2x - 6 Solve f-1(x) when x = 2..

Mathematics
1 answer:
notka56 [123]4 years ago
8 0
1) Plug in 2 into the equation:
f(x) = 2x - 6

2) f(2) = 2(2) - 6
f(2) = 4 - 6
f(2) = -2

Feel free to ask if you need me to clarify anything! :)
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The first one is $240, and the second one is $235.20
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3 years ago
What is -4k - 7 + 5k ? I need to know the steps in order to do this
MArishka [77]
-4K-7+5k
First. You have to plus the negative 4K in the 5K together which makes it K or
1K
So now you equation would be: k-7
5 0
4 years ago
Read 2 more answers
. A line goes through the points (3, -4) and (-1, 8). write the equation of the line in point-slope form. (Show the steps for ho
Allushta [10]

Answer: y= -3x + 5

Step-by-step explanation:

y2-y1 divide by x2-x1 = m

therefore you would do 8 - -4= 12 divide by -1 - 3= -4 which gives you 12 divided by  -4

m= 12/-4 aka m = -3

and to find the y intercept you should use one of the point coordination to plug it into the formula y=mx+ b

use (-1,8)

8= -3(-1) + b

8= 3+b

subtract 3 from both sides

b= 5

then plug the m and the b into y=mx + b

and you get y= -3 + 5

3 0
1 year ago
I urgently need help!!!!!!
kifflom [539]

Answer:

try C if not then A B or D

Step-by-step explanation:

7 0
3 years ago
Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.
Salsk061 [2.6K]

Given that the two functions are f(x)=9x+2 and g(x)=-9x^2-2x+1

We need to determine the value of (f \circ g)(-6)

<u>The value of </u>(f \circ g)(x)<u>:</u>

The value of (f \circ g)(x) can be determined using the formula,

(f \circ g)(x)=f[g(x)]

Substituting g(x)=-9x^2-2x+1 in the above formula, we get;

(f \circ g)(x)=f[-9x^2-2x+1]

Now, substituting x=-9 x^{2}-2 x+1 in the function f(x)=9x+2, we get;

(f \circ g)(x)=9(-9x^2-2x+1)+2

(f \circ g)(x)=-81x^2-18x+9+2

(f \circ g)(x)=-81x^2-18x+11

Thus, the value of (f \circ g)(x) is (f \circ g)(x)=-81x^2-18x+11

<u>The value of </u>(f \circ g)(-6)<u>:</u>

The value of  (f \circ g)(-6) can be determined by substituting x = -6 in the function (f \circ g)(x)=-81x^2-18x+11

Thus, we have;

(f \circ g)(-6)=-81(-6)^2-18(-6)+11

(f \circ g)(-6)=-81(36)-18(-6)+11

(f \circ g)(-6)=-2916+108+11

(f \circ g)(-6)=-2797

Thus, the value of  (f \circ g)(-6) is -2797

Hence, Option B is the correct answer.

8 0
4 years ago
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