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2 years ago

Find the distance between the points (0, 2) and (4, 5).

Mathematics

2 answers:

Nadusha1986 [10]2 years ago

7 0

Answer:

Step-by-step explanation:

$(4-0)^{2}+(5-2)^2$ (idk how to add the whole square root thing, but it is)

subtract 4-0=4 and 5-2=3 $4^{2} +3^2$ 4x4= 16 and 3x3=9, 16+9=25 then you factor it $5^2$ then you apply the radical rule (remember it's being squared) and it's equal to 5.

PilotLPTM [1.2K]2 years ago

5 0

Answer:

3/4

Step-by-step explanation:

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A multiple-choice examination has 15 questions, each with five answers, only one of which is correct. Suppose that one of the st

Alex

Answer:

0.0111% probability that he answers at least 10 questions correctly

Step-by-step explanation:

For each question, there are only two outcomes. Either it is answered correctly, or it is not. The probability of a question being answered correctly is independent from other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A multiple-choice examination has 15 questions, each with five answers, only one of which is correct.

This means that $n = 15, p = \frac{1}{5} = 0.2$

What is the probability that he answers at least 10 questions correctly?

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.2)^{10}.(0.8)^{5} = 0.0001$

$P(X = 11) = C_{15,11}.(0.2)^{11}.(0.8)^{4} = 0.000011$

$P(X = 12) = C_{15,12}.(0.2)^{12}.(0.8)^{3} \cong 0$

$P(X = 13) = C_{15,13}.(0.2)^{13}.(0.8)^{2} \cong 0$

$P(X = 14) = C_{15,14}.(0.2)^{14}.(0.8)^{1} \cong 0$

$P(X = 15) = C_{15,15}.(0.2)^{15}.(0.8)^{0} \cong 0$

$P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.0001 + 0.000011 = 0.000111$

0.0111% probability that he answers at least 10 questions correctly

3 0

3 years ago

How does a digit in the ten thousands place compare to a digit in the thousands place

Brilliant_brown [7]

It is 10x the value of the one in the thousands place

8 0

2 years ago

What is the solution to the following equation?

Snowcat [4.5K]

Answer:

A. x=13

Step-by-step explanation:

$x + 11 = 24 \\ x = 24 - 11 \\ x = 13$

5 0

3 years ago

Please help right now!!!!! Solve the system of equations below. x + y = 7 2x + 3y = 16

motikmotik

Answer:

$x=5$ and $y=2$ .

Step-by-step explanation:

We have been given a system of equations. We are asked to solve our given system.

$x+y=7...(1)$

$2x+3y=16...(2)$

From equation (1), we will get:

$x=7-y$

Upon substituting this value in equation (2), we will get:

$2(7-y)+3y=16$

$14-2y+3y=16$

$14+y=16$

$14-14+y=16-14$

$y=2$

Now, we will substitute $y=2$ in equation (1).

$x+2=7$

$x+2-2=7-2$

$x=5$

Therefore, the point $(5,2)$ is solution for our given equation.

7 0

3 years ago

The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸

Lorico [155]

Answer:

The Width of the Rectangle = $10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$ . Therefore their greatest monomial factor = $10y^6$

The Width of the Rectangle = $10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

6 0

3 years ago

Read 2 more answers