Answer:
The heaviest 5% of fruits weigh more than 747.81 grams.
Step-by-step explanation:
We are given that a particular fruit's weights are normally distributed, with a mean of 733 grams and a standard deviation of 9 grams.
Let X = <u><em>weights of the fruits</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean weight = 733 grams
= standard deviation = 9 grams
Now, we have to find that heaviest 5% of fruits weigh more than how many grams, that means;
P(X > x) = 0.05 {where x is the required weight}
P( > ) = 0.05
P(Z > ) = 0.05
In the z table the critical value of z that represents the top 5% of the area is given as 1.645, that means;
x = 747.81 grams
Hence, the heaviest 5% of fruits weigh more than 747.81 grams.
Answer:
2x^2
Step-by-step explanation:
If you're going to double x^2, you just need to multiply it by 2. You can just put the 2 in front of the x^2 because the order of operations says to do exponents before multiplication.
Answer:
wrong it is 667.95
Step-by-step explanation:
Answer:
3.6 miles
Step-by-step explanation:
For a trip of x miles, there are x-0.5 miles of it that are "additional", which makes (x-0.5)/0.1 additional tenths.
Then the charges (in dollars) are ...
... 3.50 + 0.30(x -0.5)/0.1
Adding a tip of $2 and requiring the total be less than $15 gives ...
... 3.50 + 0.30(x -0.5) + 2.00 ≤ 15.00
... 5.50 + 3(x - 0.5) ≤ 15.00 . . . . simplify a bit
... 4.00 +3x ≤ 15.00 . . . . . . . . . . simplify more
... 3x ≤ 11.00 . . . . . . subtract 4.00
... x ≤ 3.667 . . . . . . divide by 3
Miles are measured in tenths. We cannot go 3.7 miles on $15, but we can go 3.6 miles.
The answer is A bcs y=mx +c