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3 years ago

Need help with number 40 please !

Mathematics

1 answer:

zhenek [66]3 years ago

5 0

Answer: The answers are 4,100+400+3,100+2,100=9,700 the next row is 4,900+1,200+3,900+2,900=12,900

Step-by-step explanation:

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bearhunter [10]

Answer:

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Step-by-step explanation:

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3 years ago

I can’t figure this one out.

Nutka1998 [239]

the answer would be 5x-8

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3 years ago

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Solve for the missing angle : show your work

loris [4]

Answer:

Step-by-step explanation:

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Plz help me I can't figure it out

lys-0071 [83]

Answer:

$\sqrt{500}$

Step-by-step explanation:

when a value is outside of the root, then you can square it and put it back in. After you put it back in, you need to multiply it by the number that is remaining

In this case, you would square 10 which equals 100, and put it back into the root and multiply 100 by 5.

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3 years ago

A carpentry shop currently sells 66000 decoy ducks per year at a cost of 16 dollars each. In the previous year when they raised

Rus_ich [418]

Answer:

19 dollars

Step-by-step explanation:

<h2>Buckle up! This is a good one!</h2>

First we have to find the line that goes trough the two points. And it has the form :

$y=mx+b$

<em>m is often called the slope.</em>

Given the two points (66000, 16) and (51000, 21) we find m with this formula:

$m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\\m=\frac{21-16}{51000-66000} \\m=-\frac{5}{15000} \\m=-\frac{1}{3000}$

We pick the point (51000,21) and plug it into the equation of the line and we find b:

$y= mx + b\\21=(-\frac{1}{3000} )(51000)+b\\21=-17+b\\21+17=b=38$

<h3>And we have got our line equation</h3>

$y= -\frac{1}{3000}x + 38\\$

<u>Where x represents the quantity and y represents the price.</u>

<u />

<h2>The revenue</h2>

The revenue is price times quantity, since price is y and quantity is x, we get

$y=-\frac{1}{3000} x+38\\y*x=x*(-\frac{1}{3000} x+38)\\yx=-\frac{1}{3000} x^2+38x\\R(x)=-\frac{1}{3000} x^2+38x$

<h3>to maximize the revenue, we get the first derivative:</h3>

$R(x)=-\frac{1}{3000} x^2+38x\\R'(x)=-(2)\frac{1}{3000} x+38\\R'(x)=-\frac{2}{3000} x+38\\\\R'(x)=-\frac{1}{1500} x+38\\\\$

$R'(x)=-\frac{1}{1500} x+38=0\\38=\frac{1}{1500} x\\38*1500=x=57000$

So the quantity that maximizes revenue is 57000,

<h3>let's find out the price by plugging it into the equation:</h3>

$y= -\frac{1}{3000}x + 38\\y= -\frac{1}{3000}(57000) + 38\\y= -19 + 38\\y=19$

<h2>And there you go! 19 dollars is the price the carpentry shop should charge per decoy duck.</h2>

7 0

3 years ago