I’m really not sure but 216 because bass multiplied by height multiplied by width (6*6*6)
Answer:
Step-by-step explanation:
![(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B%28x%2B3%29%7D%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5C%5C%5C%5C%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%5B1%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5D)
Therefore,
<span>
2. FG= x +8 and AF = 9x - 6</span>
The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )
For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4
and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.
Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)
The distance formula is just the Pythagorean Theorem applied to an x-y graph.
You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.
is strictly increasing on [0, 5], so
and
so the integral is bounded between
