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sasho [114]
3 years ago
10

Here are two points (-3,4),(1,7) What is the slope of the line between them?

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

3/4

Step-by-step explanation:

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I’m really not sure but 216 because bass multiplied by height multiplied by width (6*6*6)
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What is the value of A when we rewrite<br> (5/2)^x +(5/2)^x+3 as A x (5/2)^x
elixir [45]

Answer:

Step-by-step explanation:

(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]

Therefore,

A=1+(\frac{5}{2})^{3}

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3 years ago
Point G is the centroid of triangle abc use the information to find the value of x.
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3 years ago
What is the distance between (−5,−4) and (-6,4)?
Helga [31]

The distance formula is:  d  =  sqrt( (x2 - x1)2 + (y2 - y1)2 )

 

For this problem, let (-5, -4) be the "first" point, so  x1 = -5  and  y2 = -4

                      and let (-6, 4) be the "second" point, so  x2 = -6  and  y2 = 4.

 

Then:  d  =  sqrt( (-6 - -5)2 + (4 - -4)2 )  =  sqrt( (-1)2 + (8)2 )  =  sqrt( 1 + 64 )  =  sqrt( 65)

 

The distance formula is just the Pythagorean Theorem applied to an x-y graph.

 

You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.

6 0
3 years ago
Will mark brainliest
faust18 [17]

x^3 is strictly increasing on [0, 5], so

\max\{x^3 \mid 0\le x\le5\} = 5^3 = 125

and

\min\{x^3 \mid 0 \le x\le5\} = 0^3 = 0

so the integral is bounded between

\displaystyle \boxed{0} \le \int_0^5x^3\,dx \le \boxed{125}

8 0
2 years ago
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