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Tresset [83]
3 years ago
11

The glasses that Pierre wants to buy cost $230. If he waits for them to go on sale next week, he can get a 15% discount. How muc

h will he save if he waits?
How much will the glasses cost if he waits?
Mathematics
1 answer:
otez555 [7]3 years ago
4 0

Answer:

$34.50 saved

Step-by-step explanation:

230 - 15% = $195.5

230 - 195.5 = 34.5 saved

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Identify the property x + 3 = x + 3
lianna [129]

the answer is communicative

5 0
3 years ago
Read 2 more answers
Simplify 24:30:12.<br> show working out and answer please
Naily [24]
First, you find the biggest number that you can divide 24, 30, and 12 by. I would go with 6, because it will simplify all the numbers into the simplest forms possible in this equation. Then, divide each number by 6.
24/6= 4
30/6= 5
12/6= 2

The answer:
4 : 5 : 2

Hope I could be of help:)
3 0
3 years ago
Solve the equation<br> (x-3)^3-( x - 1 )^3 + 7x^2 = 7(3x - 4 )
Yakvenalex [24]

Answer:

x= -1 or x = -2

Step-by-step explanation:

Your equation:

(x−3)^3−(x−1)^3+7x^2=7(3x−4)

Step 1: Simplify both sides of the equation.

x^2+24x−26=21x−28

Step 2: Subtract 21x-28 from both sides.

x^2+24x−26−(21x−28)=21x−28−(21x−28)

x^2+3x+2=0

Step 3: Factor left side of equation.

(x+1)(x+2)=0

Step 4: Set factors equal to zero.

x+1=0 or x+2=0

which equals to x=−1 or x=−2

8 0
2 years ago
Helen bought notebooks and pencils for school. The number of pencils she bought is given by 6(n-3) , where n is the number of no
pychu [463]
So the number of pencils bought can be represented by an equation: P=6(n-3), where n is the number of notebooks bought. Since Helen bought 5 notebooks, simply plug 5 into n: P=6(5-3)=6(2)=12. So Helen bought 12 pencils.
3 0
3 years ago
Suppose the time required for an auto shop to do a tune-up is normally distributed, with a mean of 102 minutes and a standard de
hammer [34]

Answer:

Step-by-step explanation:

Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean time

s = standard deviation

From the information given,

u = 102 minutes

s = 18 minutes

1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as

P(x > 120 minutes) = 1 - P(x ≤ 120)

For x = 120

z = (120 - 102)/18 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.8413

P(x > 120) = 1 - 0.8413 = 0.1587

2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as

P(x < 66 minutes)

For x = 66

z = (66 - 102)/18 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

P(x < 66 minutes) = 0.02275

4 0
3 years ago
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