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SVEN [57.7K]
3 years ago
9

Triangle A″B″C″ is formed using the translation (x + 1, y + 1) and the dilation by a scale factor of 3 from the origin. Which eq

uation explains the relationship between segment BC and segment B double prime C double prime? Coordinate plane with triangle ABC at A negative 3 comma 3, B 1 comma negative 3, and C negative 3 comma negative 3
Mathematics
2 answers:
FromTheMoon [43]3 years ago
4 0

Answer:

B''C''=3BC

Step-by-step explanation:

we know that

The length of segment B''C'' is equal to the length of segment BC multiplied by the scale factor

step 1

Find the length of segment BC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have the points

B(1,-3),C(-3,-3)

substitute the values

BC=\sqrt{(-3+3)^{2}+(-3-1)^{2}}

BC=\sqrt{(0)^{2}+(-4)^{2}}

BC=4\ units

The segment B''C'' is equal to the segment BC multiplied by the scale factor

The scale factor is 3

so

B''C''=BC(3)

B''C''=3BC

substitute

B''C''=3(4)=12\ units

almond37 [142]3 years ago
3 0

Answer:

The Answer would be C.

Step-by-step explanation:

I got it right on the flvs test.

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Two sides of an obtuse triangle measure 12 inches and 14 inches. The longest side measures 14 inches
katen-ka-za [31]

Answer:

Step-by-step explanation:

If you add the lengths of two sides, 12 and 14, you will get 28. Using the above theorem, the third side cannot be greater than or equal to 28. Therefore, the greatest possible whole-number length of the unknown side is 27.

4 0
2 years ago
Find x in this 45°-45°-90° triangle. x = 4.5√2 9 18
postnew [5]

Answer:

x = 9

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = \frac{1}{\sqrt{2} } , then

sin45° = \frac{opposite}{hypotenuse} = \frac{x}{9\sqrt{2} } = \frac{1}{\sqrt{2} } ( cross- multiply )

x × \sqrt{2} = 9\sqrt{2} ( divide both sides by \sqrt{2} )

x = 9

5 0
2 years ago
Consider the graphs of f(x) and g(x).
butalik [34]

Answer:

The value of k is -7

Step-by-step explanation:

We are given the graph of f(x) and g(x). If g(x)=f(x)+k

If we shift f(x) k unit vertical get g(x).

If k>0 then shift up

If k<0 then shift down.

f(x) and g(x) are both parabola curve.

First we find the vertex of f(x) and g(x)

Vertex of f(x) = (3,1)

Vertex of g(x) = (3,-6)

We can see change in y co-ordinate only.

f(x) shift 7 unit down to get g(x)

g(x)=f(x)-7

Therefore, The value of k is -7

5 0
3 years ago
Read 2 more answers
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
2 years ago
The first answer already given, what's the second answer (in the green box)​
chubhunter [2.5K]

Solution:

Since the graph passes through the given points, (7, 20) & (-2, 11) are the solutions of the given equation <em>y = x + ?</em>.

⇒<em>(x, y)</em> = (7, 20); (-2, 11)

Substituting the variables with (7, 20),

20 = 7 + <em>?</em>

20 - 7 = <em>?</em>

<em>?</em> = 13

Similarly,

11 = -2 +  <em>?</em>

<em>?</em> = 13

∴ <em>y</em> = 13

8 0
3 years ago
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