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Mumz [18]
3 years ago
12

I need help with my homework please answer this correctly

Mathematics
1 answer:
Levart [38]3 years ago
4 0

Your answer would be 20

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Identify each point as a solution of the system or not a solution of the system.
lubasha [3.4K]

Answer:

see below

Step-by-step explanation:

Plot the points on the given graph. The ones that fall in on a solid line at the edge of the doubly-shaded area, or fall in the doubly-shaded area, are part of the solution set.

(0, 4) on the dashed line — not a solution

(-2, 4) on red line in blue area — solution

(0, 5) in doubly-shaded area — solution

(–2, 7) in doubly-shaded area — solution

(–4, 1) in blue area — not a solution

(–1, 1) on red line outside blue area — not a solution

(–1.5, 3.5) in doubly-shaded area — solution

6 0
3 years ago
What is 35 x 5 <br><br> thnnxxxx
xxMikexx [17]
175

explaination: simple math
6 0
3 years ago
Read 2 more answers
If a circle is inscribed in a triangle which of the following must be true
KatRina [158]
A, C, E

B false because triangle is confirmed larger if the circle is fit inside of it.

D false because circle on the inside.

A true because triangle on outside

C true because it is a property of inscribed/circumscribed circles/triangles

E true because of inverse relationship
3 0
3 years ago
Read 2 more answers
What measurements of a cone can be found if you know the volume and height
Liula [17]

Answer: The base area, diameter, and radius can be found out by discovering the volume and height. Substitute the values to the corresponding variables into the formula, and then solve by simplifying and undoing operations to isolate the variable to find the diameter which is double the radius.

3 0
4 years ago
What two number multiply to -132 and add to -1
EastWind [94]

Answer:

The two numbers can be -12 and 11, or 11 and -12.

Step-by-step explanation:

xy=-132

x+y=-1

-------------

x=-1-y

(-1-y)y=-132

-y-y^2=-132

-y^2-y-(-132)=0

-y^2-y+132=0

y^2+y-132=0

factor out the trinomial,

(y-11)(y+12)=0

zero property,

y-11=0, y+12=0,

y=0+11=11,

y=0-12=-12

x+11=-1 & x+(-12)=-1

x=-1-11=-12

x=-1-(-12)=-1+12=11

5 0
4 years ago
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