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2 years ago

What is the difference between Laplace Transform and fourier Transform?

1 answer:

5 0

Real time mapping of a function to a new function is known as Fourier transforms. The new mapped function is defined for an interval of (-∞, ∞).

<span>While the Laplace transform is the counterpart, in which a function is mapped to a new function on complex plane. Functions defined for span t≥0 are used by Laplace transformation. </span>

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Determine which triangle appers to be acute?

Elena-2011 [213]

Which triangles am I supposed to choose from?

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2 years ago

Two perpendicular lines intersect at the origin. If the slope of the first line is -1/2, what is the equation of the second line

Dovator [93]

bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{2}{1}\implies 2}}$

so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-0)\implies y=2x$

5 0

2 years ago

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

$k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8$

we get

$k+1=-8\quad$

$k=-9$

$k+1=8\quad$

$k=7$

so,

$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

5 0

3 years ago

In order to clear out room for new merchandise, James decided to mark down some of the items for sale in his electronics store.

skelet666 [1.2K]

Lets day the original price of the dvd player was $100,
36% marked down means you pay $64x
64x = $41.60
100x = 100/54 x 41.60 = 4160/64 = #65.00 = original cost
similarly, stereo tuners = 100/78 x 69.42 = 6942/78 = $89 original cost
DVD = 65- 41.60 = $ 23. 40 less
Stereo = 89- 69.42 = $ 19.58 less
Diffrence is $ 3.82
so your answer is the dvd player price was reduced by $3.82 more than the stereo tuner.

8 0

3 years ago

Read 2 more answers

- 18°

Trava [24]

Answer:

use mathwsy

Step-by-step explanation:

6 0

2 years ago