Hi there,
x(x + 19) = -34
I'm going to solve your equation step-by-step.<span><span>x<span>(<span>x + 19</span>) </span></span>= <span>−34
</span></span>Step 1: Simplify both sides of the equation.<span><span><span>x2 </span>+ <span>19x </span></span>= <span>−34
</span></span>Step 2: Subtract -34 from both sides.<span><span><span><span>x2 </span>+ <span>19x </span></span>− <span>(<span>−34</span>) </span></span>= <span><span>−34 </span>− <span>(<span>−34</span>)
</span></span></span><span><span><span><span>x2 </span>+ <span>19x </span></span>+ 34 </span>= 0
</span>Step 3: Factor left side of equation.<span><span><span>(<span>x + 2</span>) </span><span>(<span>x + 17</span>) </span></span>= 0
</span>Step 4: Set factors equal to 0.<span><span><span>x + 2 </span>= <span><span><span>0<span> or </span></span>x </span>+ 17 </span></span>= 0
</span><span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−17
</span></span>Answer:<span><span>x = <span>−<span><span>2<span> or </span></span>x </span></span></span>= <span>−<span>17
Hope this helps! :)</span></span></span>
Answer: i dont understand
Step-by-step explanation:
We know, S = n/2 [ a + l ]
Here, a = 45
l = 108
Calculation of n:
a(n) = a + (n - 1)d
108 = 45 + (n - 1)1
108 - 45 = n - 1
63 + 1 = n
n = 64
Now, substitute in the expression:
S = 64/2 [ 45 + 108 ]
S = 32 [ 153 ]
S = 4896
In short, Your Answer would be 4896
Hope this helps!
Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C
Answer: Increase in number or size, at a constantly growing rate. It is one possible result of a reinforcing feedback loop that makes a population or system grow (escalate) by increasingly higher amounts.
