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3 years ago

PLEASE HELP !!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Gelneren [198K]3 years ago

6 0

Answer:

Using the given information in the problem, the final evaluated answer is 31.

Step-by-step explanation:

3² + (8 - 2) · 4 - 6/3

First, subtract 2 from 8.

3² + 6 · 4 - 6/3

Next, evaluate the exponent in 3².

9 + 6 · 4 - 6/3

Now, multiply 6 by 4.

9 + 24 - 6/3

Next, divide 3 from 6.

9 + 24 - 2

Add together 9 and 24.

33 - 2

Lastly, subtract 2 from 33.

33 - 2 = 31

So, your final answer for this equation is 31.

tester [92]3 years ago

4 0

Answer:

Step-by-step explanation:

3^2 + (8-2).4-6/3

9+6×4-6/3

9+24-2

33-2

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Help, please :) appreciate it

myrzilka [38]

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6 0

3 years ago

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

1.1 Solve the following equations: 1.1.1 (x+5)(x-3)=33

schepotkina [342]

Step-by-step explanation:

x²-3x +5x -15=33

x²-3x+5x=33+15

x²-3x+5x=48

x²+2x=48

divide both sides by 2

x²+x =24

x²= 24

x= ✓24

dunno from here

8 0

3 years ago

HELP PLSSSSSSS ILL GIVE YOU BRAINLIST

Allushta [10]

Answer:

ewdhyredhkiydg

Step-by-step explanation:

ggdsdhudgjjthfd

5 0

3 years ago

Need help :_: anyone can help me?

AlladinOne [14]

4 2/3 = 14 feet. i hope this helps because i try and for the mixed number i don't know

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3 years ago