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kobusy [5.1K]
3 years ago
10

MODELING WITH MATHEMATICS A farmer plants a garden that contains corn and pumpkins. The total area (in square

Mathematics
1 answer:
laiz [17]3 years ago
3 0

Answer:

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

Step-by-step explanation:

Given that the garden has corn and pumpkins

The expressions are:

Total area of garden: A_G = 2x^2+5x+4

Area of Corn: A_c = x^2-3x+2

Area of Pumpkins: A_p = ?

The sum of areas of corn and pumpkins is the total area of the garden.

It can be expressed mathematically as:

A_G = A_c+A_p

If we have to find the area of pumpkins,

A_p = A_G - A_c

Putting the values

A_p = (2x^2+5x+4) - (x^2-3x+2)\\A_p = 2x^2+5x+4-x^2+3x-2\\A_p = 2x^2-x^2+5x+3x+4-2\\A_p = x^2+8x+2

The equation in standard form that models area of pumpkins is:

A_p = A_G - A_c

and the area is: x^2+8x+2

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Answer:

whole triangle is 180 degrees find p with 36 and 20 then add p and q and subtract by 180

Step-by-step explanation:

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3 years ago
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Nookie1986 [14]

Answer:

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Step-by-step explanation:

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3 years ago
Please i need help it’s urgent
777dan777 [17]

Answer:

4.5

Step-by-step explanation:

6x + 42 = 18x - 12 (alternate angles)

or, 18x - 6x = 42+12

or, 12x = 54

or, x = 54/12

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8 0
3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
K(3k−6)−7k(6k+10)=12
julsineya [31]

Answer:

k = -12/77

Step-by-step explanation:

OG problem: k(3k−6)−7k(6k+10)=12

Step-by-step:

3k - 6k - 42k - 70k = 12

-3k - 42k - 70k = 12

-7k - 70k = 12

-77k = 12

k = -12/77

4 0
3 years ago
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