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3 years ago

Mr. Jones has three tables in his classroom. Each table has four

Mathematics

2 answers:

natima [27]3 years ago

5 0

Answer:

Step-by-step explanation:

you would multiply 3 tables by 4 students, that would be twelve. then 12 times 2, which is 24. Or you could find the pencils by multiplying 2 with 8 and then multiplying by 3. :)

romanna [79]3 years ago

3 0

Answer:

Step-by-step explanation:

4 students per table: 4 * 3 = 12 students

2 pencils per student: 2 * 12 = 24 pencils

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Please i need help When is the product of the square root of a prime number and a nonzero rational number a rational number?

lidiya [134]

Answer:

The product of the square root of a prime number and a nonzero rational number is a irrational number.

Step-by-step explanation:

Given that,

When is the product of the square root of a prime number and a nonzero rational number a irrational number.

We know that,

Prime number :

Prime number is that number whose has a two factor. first factor is one and second is themselves.

The square root of a prime number is irrational number.

Rational number :

Rational number is that number which is in fraction form.

For example : $\dfrac{p}{q}$

Here, p and q are integers

We need to proof the product of the square root of a prime number and a nonzero rational number is a rational number

Using given data

Suppose, the square root = √5

Rational number = $\dfrac{2}{3}$

We need to calculate the product of the square root of a prime number and a rational number

Using formula of product

$R=P\timesQ$

Where, P = square root of a prime number

Q= rational number

Put the value into the formula

$R=\sqrt{5}\times\dfrac{2}{3}$

$R=\dfrac{2\sqrt{5}}{3}$

Hence, The product of the square root of a prime number and a nonzero rational number is a irrational number.

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3 years ago

Picture Inside :) Help me please

Svetlanka [38]

Answer:

Step-by-step explanation:

are you in 6th grade what the, well the answer is 35.8

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3 years ago

At birth bens dad puts $1 in a savings account. Each year on his birthday he goves him double the amount in his account. Write a

jonny [76]

This problem Is an example of geometrica progression. The formula for the sum of geometric progression is:

S = a[(r^n)-1] / (r – 1)

Where s is the sum

a is the first term = 1

r is the common ratio = 2 ( because it doubles every year

n is the number of terms = (19) since the first term is when he was born which he still 0

s = S = 1[(2^19)-1] / (2 – 1)

s = $524,287

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3 years ago

How to divide a small number by a bigger number?

EastWind [94]

To divide a small number by a bigger number, just see how many times the smaller number fits into the bigger number.

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3 years ago

Given that , the _____ justifies the conclusion that ∆ABD ≅ ∆AEC.

trasher [3.6K]

AAS Postulate

It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.

Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.

Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!

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3 years ago

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