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UkoKoshka [18]
4 years ago
12

When the flower below is rotated clockwise 90 degrees where will the red petal be in the image?

Mathematics
2 answers:
Dima020 [189]4 years ago
6 0
There appears to not be an image attached but if it was turned 90 degrees that would be about a 1/4
wel4 years ago
5 0
Hey I need a pic then I'll answer in the comments. If no pic then if a red petal is directly facing a side, then it will be facing the adjacent clockwise side.
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The answer is B. 829 feet per second.

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What is the slope of a line that passes (4, 10) and (1, 10)
SpyIntel [72]

Answer:

The slope of the a straight line is given by the ratio of the Rise to the Run

of the line. The rise between the given points is zero.

The slope of the line that passes through the points (4, 10) and (1, 10) is zero.

Step-by-step explanation:

The given points are; (4, 10) and (1, 10)

The slope of a line, m, is given by the following formula;

Where;

(x₁, y₁) = (4, 10) and (x₂. y₂) = (1, 10), we get;

The slope of the line that passes through the points (4, 10) and (1, 10) is 0.

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2 years ago
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A basketball player completed ​44.2% of his field goals in the most recent season. He made 287 field goals. How many did he​ att
Andrej [43]

44.2%= 287

Let the total attempt = x

(287/x) ×100 = 44.2

287/x = 44.2/100

287/x = 0.442

x = 287/0.442

<h3>x= <u>649 </u></h3>

Hope this will help...

5 0
3 years ago
If 20 tickets to a carnival cost $120.00, make a
aivan3 [116]
120/20=6 so it’s six dollars a ticket
1=$6
3=$18
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3 years ago
Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at
Dafna1 [17]

Answer:

\huge\boxed{  \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • conic sections
  • PEMDAS
<h3>tips and formulas:</h3>
  • \sf hyperbola \:equation :  \\  \sf  \frac{ {x}^{2} }{ {a}^{2} }   -  \frac{ {y}^{2} }{ {b}^{2} }  = 1
  • vertices of hyperbola:(±a,0) and (0,±b) if reversed
  • \sf \: asymptotes :  \\ y =   \pm\frac{b}{a} x
<h3>given:</h3>
  • vertices: (0,±10)
  • the hyperbola equation is inversed since the vertices is (0,±10)
  • asymptotes:\pm \frac{5}{6}x
<h3>let's solve:</h3>
  • the asymptotes are in simplest and we know b is ±10

according to the question

  1. y =  \sf  \frac{5 \times 2}{6 \times 2} x \\ y =  \frac{10}{12} x

therefore we got

  • a=12
  • b=10

note: the equation will be inversed

let's create the equation:

  1. \sf substitute \: the \: value \: of \: a \: and \: b :  \\  \sf  \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1

3 0
3 years ago
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