Answer:
B) -5, 5, -7, 7
Step-by-step explanation:
3x² - bx + 2
factor:
(3x - 2 )(x - 1) = 3x² - (5)x + 2 so 5 does work
(3x - 1 )(x - 2) = 3x² - (7)x + 2 so 7 does work
(3x + 2 )(x + 1) = 3x² + 5x +2 = 3x² - (-5)x + 2 so -5 does work
(3x + 1 )(x + 2) = 3x² + 7x + 2 = 3x² - (-7)x + 2 so -7 does work
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
Answer:
E. 44 meters
Step-by-step explanation:
The function that models the distance covered by the object is
where s(t) is in meters and t is in seconds.
The distance covered by the object after 1 second is
The distance covered by the object after 1 second is
The distance covered between 1 second and 5 seconds is
50-6=44m
Answer:
4K
Step-by-step explanation:
= K ( multiply both sides by 24 to clear the fraction )
J = 24K ( divide both sides by 6 )
= 4K
