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Elza [17]
3 years ago
15

A missile uses an internal computer clock to measure time in tenths of a second. The missile guidance system needs the time from

launch, in seconds, in order to calculate its distance from the launch site. It obtains this by multiplying the computer clock time by 0.1. So, for example, a reading of 50 tenths of a second is 5 seconds. For one particular missile system, the conversion factor of 0.1 is stored in 8 bits as the binary number 0.000110012.
The missile’s internal computer clock shows 200 tenths of a second. Convert this to seconds using your result from Part (i) of this question. Do not round your answer. The missile guidance system now records that it has travelled for this number of seconds.
Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0

Using proportions, it is found that the missile's internal computer clock is of 20 seconds.

  • According to the information given, this question can be solved by proportions, using a rule of three.

<u>50 tenths of a second is equivalent to 5 seconds,</u> and we want to find the <u>equivalent to 200 tenths</u> of a second, thus, the rule of three is:

50 tenths - 5 seconds

200 tenths - x seconds

Applying cross multiplication:

50x = 5(200)

50x = 1000

x = \frac{1000}{50}

x = 20

The missile's internal computer clock is of 20 seconds.

A similar problem is given at brainly.com/question/24372153

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Olenka [21]

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3 years ago
Given that LM and LN are tangent to the circle and that the measure of angle MLN = 75.86, find the measure of arc MN.
siniylev [52]

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7 0
3 years ago
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