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emmainna [20.7K]

3 years ago

10

Which of the following steps were applied to ABC obtain A'B'C' ?

2 answers:

ankoles [38]3 years ago

8 0

Answer:

Shifted 3 units right and 2 units up.

Step-by-step explanation:

Given : Graph.

To find : Which of the following steps were applied to ABC obtain A'B'C'.

Solution : We have given Graph.

Original Triangle = ABC

Translated Triangle = A'B'C'.

Coordinate

A (2, 5)→→→A '(5, 7)

B( 3 ,10)→→→B'(6 ,12)

C( 7 ,5)→→→C'( 10 ,7)

We can see x coordinate increased by 3 and y coordinates increased by 2.

A (2+3, 5+2)→→→A '(5, 7)

B( 3+3 ,10+2)→→→B'(6 ,12)

C( 7+3 ,5+2)→→→C'( 10 ,7)

Therefore, Shifted 3 units right and 2 units up.

Greeley [361]3 years ago

5 0

A is located at (2,5)

A' is located at (5,7)

Subtract the X's and then the Y's to get how much it moved:

5-2 = 3 unit shift to the right.

7-5 = 2 unit shift up.

The answer would be A.

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4 years ago

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2 years ago

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Tomtit [17]

Answer:

Step-by-step explanation:

The area for a triangle is

$A=\frac{1}{2}bh$

Our base is given as x, the height is given as 1 more than 6 times the base which looks like this: 6x + 1. We know that the area is 13, so filling in everything:

$13=\frac{1}{2} (6x+1)(x)$

We can get rid of the denominator of 2 by multiplying it on both sides to get:

$26=(6x+1)(x)$ and simplifying a bit:

$26=6x^2+x$

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3 0

2 years ago

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7nadin3 [17]

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3 years ago

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suter [353]

Answer:

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Step-by-step explanation:

2x = x - 10

you then divide

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3 years ago