Answer:
5/12
Step-by-step explanation:
Answer:
x = 1
Step-by-step explanation:
f(x) = 3x + 3
f(x) = 6
=> 3x + 3 = 6
=> 3x = 3
=> x = 1
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1) eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
Answer:
b = 6i then a = -6i
b = -6i then a = 6i
Step-by-step explanation:
a+b=0
ab=36
a = -b
a(b) = 36
-b * b = 36
- b^2 = 36
b^2 = -36
Take the square root of each side
sqrt(b^2) = sqrt(-36)
b =± 6i
a = - (± 6i)
so b = 6i then a = -6i
b = -6i then a = 6i
Can you provide a picture ?? or some sort of context
