Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
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Answer:
hw que no te he podido contestar por la tarde pero si te llamo en el tercero para que
Answer:
Huw spends £48 on his social life
Answer:The object will hit the ground after 5 seconds
Step-by-step explanation:
Given height of tower =80 ft
h=-16
+64t+80
When the object will hit the ground its height=0
0=-16
+64t+80
Multiplying both sides by -1
16t²-64t-80=0
Dividing by 16 both sides
t²-4t-5=0
(t-5)(t+1)=0
t=5 or -1
So t=5 since time cannot be negative
The object will fall after 5 seconds