Answer:
a
Step-by-step explanation:
b, c, d are all x2 (a real linear equation does not have square or it will become Quadratic equation )
Answer:
Only option B is correct, i.e. all real values of x except x = 2.
Step-by-step explanation:
Given the functions are C(x) = 5/(x-2) and D(x) = (x+3)
Finding (C·D)(x) :-
(C·D)(x) = C(x) * D(x)
(C·D)(x) = 5/(x-2) * (x+3)
(C·D)(x) = 5(x+3) / (x-2)
(C·D)(x) = (5x+15) / (x-2)
Let y(x) = (C·D)(x) = (5x+15) / (x-2)
According to definition of functions, the rational functions are defined for all Real values except the one at which denominator is zero.
It means domain will be all Real values except (x-2)≠0 or x≠2.
Hence, only option B is correct, i.e. all real values of x except x = 2.
Answer:
The given table is
Hours. Earnings per hour.
0
4
8
12
Now, the unit rate is $8.25 per hour, according to the proble, this is the constant ratio of change, that means, we only need to multiply the number of hours with the unit rate.

<h3>Therefore, the complete table is</h3>
Hours. Earnings per hour.
0 0
4 33
8 66
12 99
Answer:
(a)
(b)
(c)
Step-by-step explanation:
Number of juniors who attended prom,n(J)=28
Number of seniors who attended prom,n(S)=97
- Total of those who attended prom=125
Number of juniors who did not attend prom,n(J')=56
Number of seniors who did not attend prom,n(S')=19
- Total of those who attended prom=75
- Total Number of students=200
(a) P (a junior who did not attend prom)

(b)


(c)P (junior | attended prom)

