Answer:
Step-by-step explanation
You must find the common denominator for all of them.
A is correct. 13 x 2 is 26 and 14 x 2 is 28. Therefore, 13/14 is greater than 25/28.
B is not correct. 4 x 5 is 20 and 9 x 5 is 45. 4/9 is actually less than 21/45.
C is not correct. 5 x 2 is 10 and 6 x 2 is 12. 5/6 is actually less than 11/12.
D is not correct. 4 x 5 is 20 and 5 x 5 is 25. 4/5 is actually less than 8/25.
<span><span>√<span><span><span>(<span><span>3<span>x4</span></span><span>y3</span></span>)</span>2</span>⋅<span>(<span><span>6x</span>y</span>)</span></span></span><span><span><span><span>3<span>x4</span></span><span>y3</span></span>2</span>⋅<span><span>6x</span>y</span></span></span>Pull terms out from under the radical.<span><span><span>3<span>x4</span></span><span>y3</span></span><span>√<span><span>6x</span><span>y</span></span></span></span>
The inverse of a function f(x) is f⁻¹(x) = 4x + 3 after using the concept of the inverse of a function.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
To find the inverse of a function:
Interchange the f(x) and x
f(x) → x
x → f⁻¹(x)
Make the subject f(x);
Thus, the inverse of a function f(x) is f⁻¹(x) = 4x + 3 after using the concept of the inverse of a function.
Learn more about the function here:
brainly.com/question/5245372
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Given:
A figure of a circle and two secants on the circle from the outside of the circle.
To find:
The measure of angle KLM.
Solution:
According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.
Using intersecting secant theorem, we get
Multiply both sides by 2.
Isolate the variable x.
Divide both sides by 7.
Now,
Therefore, the measure of angle KLM is 113 degrees.
and 
are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
is the function evaluated at the <span>9th month
is the function evaluated at the 3rd month ![m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}](https://tex.z-dn.net/?f=m%3D%20%5Cfrac%7B%5B9%5E%7B2%7D-24%289%29%2B108%5D-%5B3%5E%7B2%7D-24%283%29%2B108%5D%7D%7B9-3%7D%20)
