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sesenic [268]
3 years ago
9

Kevin works for a company which produces printers. A printer sells for $163.95 and costs $48.28 to produce. In one month, Kevin’

s company sold 427 printers, earning a profit of 22,599.09. How great were the company’s non-production overhead expenses, to the nearest dollar?
a) $13,410
b) $20,616
c) $24,809
d) $26,792
Mathematics
1 answer:
victus00 [196]3 years ago
3 0

Answer:

Option D $26,792

Step-by-step explanation:

When producing 427 printers, the cost of production is 427*$48.28=$20,615.56

When selling each printer, profit per printer is $163.95 - $48.28= $115.67

Total money after selling the 427 printers is 427*$163.95 =$70006.65

Subtracting cost of production from value of sales we deduce

$70006.65-$20,615.56=$49391.09

Non-profit overhead expenses will be the difference between the expected profit and the actual profit earned

$49391.09 -$22,599.09.=$26,792

Therefore, option D, $26,792 is the right choice

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X-3/7=4 what is x plz help me
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Answer:

28/3 =9.33

Step-by-step explanation:

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4 years ago
Which set of integers is a Pythagorean triple and are the side lengths of a right triangle?
m_a_m_a [10]

Answer: the integers that is a Pythagorean triple and are the side lengths of a right triangle is

C. 9, 40, 41

Step-by-step explanation:

A Pythagorean triple is a set of three numbers which satisfy the Pythagoras theorem. The Pythagoras theorem is expressed as

Hypotenuse^2 = opposite side^2 + adjacent side^2

Let us try each set of numbers.

A. 20,23,28

28^2 = 20^ + 23^2

784 = 400 + 529 = 929

Since both sides of the equation are not equal, the set of numbers is not a Pythagoras triple.

B. 18, 26, 44

44^2 = 18^ + 26^2

1936 = 324 + 676 = 1000

Since both sides of the equation are not equal, the set of numbers is not a Pythagoras triple.

C. 9, 40, 41

41^2 = 9^ + 40^2

1681 = 81 + 1600 = 1681

Since both sides of the equation are equal, the set of numbers is a Pythagoras triple.

D. 8, 20, 32

32^2 = 20^ + 8^2

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Since both sides of the equation are not equal, the set of numbers is not a Pythagoras triple.

7 0
3 years ago
Simplify 4(a−b)+6b PLZ
yaroslaw [1]

Expand

4a - 4b + 6b

Collect like terms

4a + (-4b + 6b)

Simplify

<u>4a + 2b</u>

7 0
4 years ago
How do I solve this question?
nirvana33 [79]
First subtract 11b from both sides and then 11b would cancel out and the 14 would be 3b and then you subtract 3 from both sides and so it would be 3 so you divide 3b by 3 so it would be 3 greater than or equal to b.
8 0
3 years ago
Read 2 more answers
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Phantasy [73]
I’m pretty sure it’s the 2nd one
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3 years ago
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