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Olenka [21]
2 years ago
11

The cargo carrying part of Billy‘s truck has a length of 8.3 m a width of 3 m and a height of 4.2 m. What is the maximum volume

of sand that Billy‘s truck can carry?

Mathematics
1 answer:
madam [21]2 years ago
8 0
You're really just finding the volume of the cargo-carry part.

V= L x W x H

V= 8.3m x 3m x 4.2m

V= 104.58 m3 or 105 m3 (rounded)

ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
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Arte-miy333 [17]

Answer:

total number of people on Friday = 285

total number of people on Saturday = 355

total increment = 355-285 = 70

total increase percentage = 70÷285*100

= 24.56%

hope it helps!

3 0
2 years ago
Angle M and Angle N are vertical angles. The measure of Angle M is 3x – 18. The measure of Angle N is x + 30.
torisob [31]

Answer:

24 = x

54° = Measure\:of\:Angle\:N

54° = Measure\:of\:Angle\:M

Step-by-step explanation:

Vertical Angles are congruent, so set the two expressions equal to each other:

[x + 30]° = [3x - 18]°

-[3x]° - [3x]°

___________

−18° = 30° - [2x]°

- 30° - 30°

____________

−48° = [−2x]°

____ ___

−2° −2°

24° = x [Plug this back into both expressions to get both <em>m</em>∠<em>N</em> and <em>m</em>∠<em>M</em> at 54°.]

I am joyous to assist you anytime.

5 0
3 years ago
What is 2 to the power of 2?
padilas [110]
Okay, so you are talking about exponents, so what you are talking about is 2², to find the answer to the exponent you multiply the same number as many times as the exponent (little number) says, so in here we are going to multiply 2 x 2 and the answer is 4. So 2 to the power of 2 is 4.
5 0
3 years ago
Somebody explain pls!!!!!
Furkat [3]

Step-by-step explanation:

Using log properties

log_{7}(rz {}^{12} )

log_{7}(r)  +  log_{7}(z {}^{12} )

Then

log_{7}(r)  + 12 log_{7}(z)

Plug in the knowns

- 7.87 + 12( - 12.59)

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5 0
8 months ago
John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
vaieri [72.5K]

Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

56 people came into the store.

23 bought something in the store.

(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

So

P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

8 0
3 years ago
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