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PIT_PIT [208]
2 years ago
9

Find the work done by the force f(x)=3x+7 in moving a particle from x=1 to x=3

Mathematics
1 answer:
andrew11 [14]2 years ago
4 0

Answer:

26

Step-by-step explanation:

W = ∫ f(x) dx

W = ∫₁³ (3x + 7) dx

W = (1.5x² + 7x) |₁³

W = (1.5(3)² + 7(3)) − (1.5(1)² + 7(1))

W = 26

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3 years ago
Hi there. I am having trouble with calculating in base 4. The problem is 2014-324=
Arlecino [84]

Answer:

The required answer is (201)_4-(32)_4=(103)_4.

Step-by-step explanation:

Consider the provided numbers:

We need to subtract in base 4.

(201)_4-(32)_4

The place value of 201 is:

1 is at units place, 0 is at four's place and 2 is at 4 squared place.

The place value of 32 is:

2 is at units place and 3 is at four's place.

201

- 32

Start subtracting the numbers from the unit place.

Here, we need to subtract 2 from 1, which is not possible so borrow 4 from the four's place but there is 0 at four's place so borrow from 4 squared place and change 2 to 1.

Also change 0 to 4 because we have borrow 4 from squared place.

Now 1 can borrow 4 from the four's place which will become 1+4=5 and change 4 at four's place to 3.

Now the number will look like this:

135

- 32

Now subtract the number as shown.

135

<u>- 32</u>

103

Hence, the required answer is (201)_4-(32)_4=(103)_4.

4 0
3 years ago
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Airida [17]
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4 0
2 years ago
Solve for y. Please help!!
Nadya [2.5K]

Answer:

y=3\sqrt{7}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

we know that

In the right triangle ABD

tan(

In the right triangle BCD

tan(

remember that

m< BAD=m<CBD

therefore

tan(

equate the equations

y/9=7/y

y^{2}=63

y=3\sqrt{7}\ units

7 0
3 years ago
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