Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.
Answer:
c)5676.16
Step-by-step explanation:
formula =0.5 X A X BX H
= 0.5 * 22.4*22.8*18.1
Answer:
congruent
Step-by-step explanation:
Given parallel lines cut by transversal, corresponding angles are <u><em>congruent</em></u>.
I’m pretty sure it will be the last one f(x)=(3x+1)(2x-5).