In triangle KLP, k = 13mi, l = 10mi, and p = 8mi. Find measurement K to the nearest 10th
1 answer:
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Answer:
See attachment
Step-by-step explanation:
First solve this like a normal equation:
-3x - 6 > 9
Add 6 to both sides:
-3x > 9 + 6
-3x > 15
Divide by -3 and remember to switch the inequality sign:
x < 15/(-3)
x < -5
Think about the graph of x = -5. It's a vertical line crossing the y-axis at x = -5. Now, we have x is less than -5. That means all the values less than -5 should be viable solutions. So, shade the part of the graph to the left of the vertical line.
Also, since we have x < -5 and not x ≤ -5, the line should be dotted.
See graph attached.
<em>~ an aesthetics lover</em>
Answer:
Per minute value fee would be the slope of the line.
Step-by-step explanation:
Given:
Per minute charges by the phone company = $ 0.50
Connection fee (fixed) charged by company = $ 1.0
We have to represent the total cost in terms of y and also explain the slope of the line.
According to the question:
Let the number of minutes be "x" .
And the total cost charged be "y" .
So,
The total cost = (No. of minutes)(Per minute charge) + Connection fee
Re-arranging in term of x and y.
⇒
⇒ ...equation (i)
Slope- intercept form: m is the slope and b is the y-is intercept.
⇒ Comparing equation (i) with the slope- intercept form.
⇒ and
So,
The slope of the line is 0.50 which is also represented by the per minute value of the call.
Per minute value fee would be the slope of the line.
Answer:
y = 8 is the equation of tangent.
Step-by-step explanation:
The equation of the tangent to the circle at (-6,8) is of the form:
y = mx + c
where m is the slope of the tangent and c is the y-intercept.
The point (-6,8) lies on the circle and the tangent line as well.
Hence (-6,8) satisfies the line equation:
8 = m(-6) + c ⇒ c-6m = 8 -------------1
We know that slope of two perpendicular lines are related as:
At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.
Hence :
We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.
= ∞
Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0
Hence m=0
Putting m=0 in equation 1 we get:
c = 8
The equation of tangent line at (-6,8) is:
y = 8