Answer:
166 packs
Step-by-step explanation:
Data obtained from the question include:
Total pack of paper needed by Bret 450 packs
Bret currently has = 284 packs
The remaining packs of paper needed by Bret = 450 — 284 = 166 packs
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
The formula for the area of the triangles is base x hight divided by 2 (bh/2)
The formula for the square is length times width (l x w)
therefore...
bh/2 = (12)(6) / 2 = 36 (this is the area of one triangle)
then you need to times 36 by 4 because you have 4 triangles.
36 x 4 = 144
l x w = 12 x 12 = 144 (this is the area of the square)
last you need to add the area of the triangles (144) and the area of the square (144) because that will give you the total surface area of the shape.
144+144= 288
so your answer is 288cm squared (288cm2)
11.66 or 12
Step-by-step explanation:
c^2 = a^2 + b^2
19^2 = 15^2 + b^2
361 = 225 + b^2
361 - 225 = b^2
136 = b^2
(square root of both sides)
b = 11.66or 12
No such thing as cot (61,4). I think you meant to say cot (61.4°). See the difference?
So, cot (61.4°) is approximately -0.139844.
Rounded to 3 decimal places we get -0.140.
