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Zolol [24]
3 years ago
11

Hello I don't know how to do this, can somebody explain me? Graph the linear function w(x)= 3/5x+2 ​

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

Answer:

okay so u have a graph

u go to the center 0,0

u go up 2 places

then up 3 ove to the left 5

the repeat that step

u get it

Step-by-step explanation:

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Construct a 96% confidence interval if a sampling distribution has a mean of 20, a standard deviation of 5, and a size of 100.
MAXImum [283]

Using the t-distribution, the 96% confidence interval is given as follows:

(18.96, 21.04).

<h3>What is a t-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm t\frac{s}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • t is the critical value.
  • n is the sample size.
  • s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 96% confidence interval, with 100 - 1 = 99 df, is t = 2.0812.

The parameters are given as follows:

\overline{x} = 20, s = 5, n = 100

Hence the bounds of the interval are:

\overline{x} - t\frac{s}{\sqrt{n}} = 20 - 2.0812\frac{5}{\sqrt{100}} = 18.96

\overline{x} + t\frac{s}{\sqrt{n}} = 20 + 2.0812\frac{5}{\sqrt{100}} = 21.04

More can be learned about the t-distribution at brainly.com/question/16162795

#SPJ1

6 0
2 years ago
How do I find LN? On the line segment
kaheart [24]
You add 25 and 12 i think
4 0
3 years ago
Read 2 more answers
For brainliest answer this ASAP
krok68 [10]

Answer:

The hypotenuse of a right triangle is 4m longer than the shorter leg and 2m longer than the longer leg. What are the lengths of the sides?

Just for variety, consider the hypotenuse = h, the short leg h-4 and the long leg h-2.

c^2 = a^2 + b^2; so h^2 = (h-4)^2 + (h-2)^2; h^2 = h^2 - 8h + 16 +h^2 -4h +4;

h^2 -12h +20 = 0 factors to (h - 10)(h - 2) = 0 so h = 2 or h = 10

Since (h - 2) = (2 - 2) = 0 and a triangle cannot have a side of zero length, 10 is the length of the hypotenuse.

h^2 = (h-4)^2 + (h-2); 10^2 = (10-4)^2 + (10-2); (10)^2 = (6)^2 + (8)

The hypotenuse is 10 cm, short leg 6 cm and long leg 8 cm.

5 0
3 years ago
Multiply and Simplify<br> b^2*b^4*b*b^5
attashe74 [19]
B x b x b x b x b x b x b x  b x b x b x b x b x b x b x b
7 0
3 years ago
Read 2 more answers
Ayuda es para mañana El estudiante 1 y el estudiante 2 están a 53 metros, uno del otro. El estudiante 1, desde su posición, ve u
hram777 [196]

Answer:

La opción correcta es;

Estudiante 2, ya que está aproximadamente a 32,39 metros de distancia

Step-by-step explanation:

Los parámetros dados son;

La distancia entre los dos estudiantes = 53 metros

El ángulo medido entre la línea del Estudiante 1 a la caja fuerte y el Estudiante 1 y el Estudiante 2 = 37 °

El ángulo medido entre la línea del Estudiante 2 a la caja fuerte y el Estudiante 2 y el Estudiante 1 = 43 °

Dado que los dos estudiantes y la caja fuerte forman los vértices de un triángulo, tenemos;

Sea θ el ángulo del triángulo opuesto a la distancia entre los dos estudiantes

Por lo tanto;

θ + 43 ° + 37 ° = 180 ° (teorema de suma de ángulos)

θ = 180 ° - (43 ° + 37 °) = 100 °

Por regla del seno, tenemos;

a / (sin (A) = b / sin (B)

Por lo tanto;

53 / (sin (100 °)) = b / (sin (37 °)) = c / (sin (43 °))

Lo que da;

b = (sin (37 °)) × 53 / (sin (100 °)) = 32,39 metros

c = (sin (43 grados)) × 53 / (sin (100 grados)) = 36,7 metros

Por lo tanto, el Estudiante 2 está más cerca, ya que está aproximadamente a 32,39 metros de distancia.

6 0
3 years ago
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