Answer:
880 high-quality version
Step-by-step explanation:
I think the below is your full question:
<em>A Web music store offers two versions of a popular song. The size of the standard version is 2.1megabytes (MB). The size of the high-quality version is 4.5 MB. Yesterday, there were 1290 downloads of the song, for a total download size of 4821 MB. How many downloads of the high-quality version were there?</em>
Here is my answer:
Let x is the number of high-quality version
So the number of standard version= 1290 - x
We also know: total download size of 4821 MB. which means:
4.5x + 2.1(1290-x) = 4821
<=> 4.5x+2709-2.1x=4821
<=> 2.4x=2112
<=> x=880
So there were 880 high-quality version
Answer:
The answer is below
Step-by-step explanation:
Given the function as:
f(x)=5sin(πx / 15)+180,
a) The angular frequency (ω) = 2π * frequency
but ω = π/15, hence:
π/15 = 2π * frequency
frequency = (π/15)/2π
frequency = 1/30 hertz
Period (T) = 1/frequency = 1/(1/30) = 30 seconds
b) The period is 30 seconds. This means that it reaches the maximum temperature every 30 seconds.
In one hour (3600 s), the number of times the function reaches a maximum temperature = 3600 s / 30 s = 120
Answer:
1. one orange x tile
2. five blue - tiles
3. x-5
Step-by-step explanation:
Solution:x^2+3x-4=(x+4)(x-1)>0,
therefore, the x range is (-∞,-4)∪(1,+∞).
Answer:(-∞,-4)∪(1,+∞).[
Answer:
$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Normally distributed with mean $480 and standard deviation $20.
This means that 
How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?
This is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.
$512.90 should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05
