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dangina [55]
2 years ago
10

Where is long-wavelength radiation created?

Biology
1 answer:
Ivahew [28]2 years ago
4 0

On the earth surface

Explanation:

The long-wavelength radiation is created on the earth surface when electromagnetic radiation is re-emitted.

  • The sun releases radiation in form of short-wave.
  • They are usually more energetic and with short wavelength and a high frequency.
  • When they interact with materials on the earth, they are radiated back as long-wavelength radiation that usually causes heat.
  • Ultraviolet rays and other high energy waves are emitted from the sun because it is a very hot body.
  • When these radiations enters the earth, they are re-radiated back as long waves with lower energy.
  • Earth is cooler than the sun
  • When some of the short waves for example, the ultraviolet rays gets to the surface, it is absorbed and re-radiated back.
  • When the short waves are absorbed, they lose some of their their energy to the earth surface.
  • The remainder is radiated back as less energetic long waves.
  • The hotter a body is, the more energetic the radiation it releases.

learn more:

Electromagnetic radiation brainly.com/question/6818046

#learnwithBrainly

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En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
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Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

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