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azamat
3 years ago
14

What is the distance between the point 10,7 and 2,7 unit?

Mathematics
2 answers:
Tom [10]3 years ago
4 0
It is a distance of 8
Kay [80]3 years ago
3 0

It is eather 9 or 10

You might be interested in
Simplify.<br><br><br><br> –7 + 8 + 10 ÷ (–2)
Scrat [10]
<span>BEDMAS says we do division first, then we can solve the rest:

–7 + 8 + (10 ÷ (–2))
</span><span>-7 + 8 - 5
</span>= - 4

Hope this helps! 




4 0
3 years ago
How to use inverse cosin
Alecsey [184]

Answer:

sec

Step-by-step explanation:

1/cosin = sec or cosin^-1

4 0
2 years ago
What is X-5+10x+3???
Alekssandra [29.7K]

Answer:

-2+11x

Step-by-step explanation:

Combine like terms

(-5+3)+(x+10x)

-5+3 = -2

x+10x = 11x

-2+11x

8 0
3 years ago
The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t
Doss [256]

Answer:

First Case:

\displaystyle p=\frac{5}{2}\text{ and } d=-2

Second Case:

\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

6p+2, 4p^2-10, \text{ and } 4p+3

Since this is an arithmetic sequence, each subsequent term is <em>d</em> more than the previous term, where <em>d</em> is our common difference.

Therefore, we can write the second term as;

4p^2-10=(6p+2)+d

And, likewise, for the third term:

4p+3=(6p+2)+2d

Let's solve for <em>d</em> for each of the equations.

Subtracting in the first equation yields:

d=4p^2-6p-12

And for the second equation:

2d=-2p+1

To avoid fractions, let's multiply the first equation by 2. Hence:

2d=8p^2-12p-24

Therefore:

8p^2-12p-24=-2p+1

Simplifying yields:

8p^2-10p-25=0

Solve for <em>p</em>. We can factor:

8p^2+10p-20p-25=0

Factor:

2p(4p+5)-5(4p+5)=0

Grouping:

(2p-5)(4p+5)=0

Zero Product Property:

\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}

Then, we can use the second equation to solve for <em>d</em>. So:

2d_1=-2p_1+1

Substituting:

\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}

So, for the first case, <em>p</em> is 5/2 and <em>d</em> is -2.

Likewise, for the second case:

\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}

So, for the second case, <em>p </em>is -5/4, and <em>d</em> is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0
3 years ago
Calculate the lateral surface area of the rectangular prism:
bekas [8.4K]
Find the area of all six rectangular faces of the prism. (A= l x b)

A1: 3.1 x 5 = 15.5
A2: 7.4 x 3.1 = 22.94
A3: 5 x 7.4 = 37
A4: 3.1 x 7.4 = 22.94
A5: 7.4 x 5 = 37
A6: 3.1 x 5 = 15.5

Add all answers together to get your answer of 150.88 cm^2.
Hope this helps!!
8 0
3 years ago
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