Answer:
28 cubs
Step-by-step explanation:
Since one and a half bear produces one and a half cub, then 6 bears will produce 6 cubs in one and a half days.
We need to find 7 days, though but we have the rate for six bears for 1.5 days which 6 bears one a half day.
What is the rate for a day?
6/1.5 =
6 bears produce 4 cubs a day.
Now just do 4 x 7
4 x 7 = 28
Therefore, 6 bears produce 28 cubs in 7 days.
I would say that the third one is false.
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
Rounding 2.199. The tenths digit is 1, which is 4 or less, so you will round down. Re-write 2.199 without the decimal places: 2 . So 2.199 rounds to 2.
Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P()= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!
