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dusya [7]
3 years ago
11

Hellen has 10 sweets,shelly has 30 sweets.Faith has 4 fewer sweets than the average number of sweets that hellen,shelly and fait

h have.How many sweets do they have altogether
Mathematics
1 answer:
allsm [11]3 years ago
7 0

Answer:

The sum of all the sweets is 54 sweets

Step-by-step explanation:

Here, we want to calculate the number of sweets the three have altogether.

Let the number of sweet Faith has be x

Mathematically;

Faith has 4 sweets fewer than the average number of sweets

The average is the sum of all the sweets divided by 3

The average will be (10 + 30 + x)/3

Thus;

(10 + 30 + x)/3 - 4 = x

(40 + x)/3 = x + 4

40 + x = 3(x + 4)

40 + x = 3x + 12

40-12 = 3x -x

28 = 2x

x = 28/2

x = 14 sweets

So the sum of all the sweets would be 10 + 30 + 14 = 54 sweets

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3p = 9 ( divide both sides by 3 )

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