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Rzqust [24]
3 years ago
13

Pls help with this please

Mathematics
2 answers:
Marina86 [1]3 years ago
6 0
You have to do 2 5/8 4 times but in a picture or scrap
Nikitich [7]3 years ago
3 0
3. The answer is 5
4. The answer is 5
5. The answer is 16/3
6. The answer is 8
7. The answer is 3/2
8. The answer is 8
9.The answer is 6
10. The answer is 21/5
11. The answer is 10/3
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PLEASE HELP WILL GIVE BRAINLIEST<br> Answer all parts of the question please!
Schach [20]
A: l x w = a formula for area
l = w + 48 length
w(w+48) = 3024 substitute l with w+48
w^2 + 48w -3024=0 —solution to part A

B: w^2 + 48w - 3024 = 0 factor
(w-36)(w+84) = 0
Solutions for width = 36,-84
A width can’t be negative, so the width is 36 inches


7 0
3 years ago
A theatre collected $100 from all the 100 attendees in the audience. The prices of the tickets were $10 for adults, $3 for frien
monitta
You can write a system of equations, I'm pretty sure. 
the first equation would be 
10a+3f+.5c=100
and 
a+f+c=100

For the first equation, its the price of each ticket that adds up to 100 tickets
For the second equation, its the amount of people that adds up to 100 people.

I'm pretty sure this is the route to go but I haven't solved it for myself (yet) I'll probably comment the answer if you need me to
4 0
3 years ago
1J orge uses 2 ounces of sauce for every serving of spaghetti he makes. Complete the table below to show the relationship betwee
N76 [4]

Answer:

57

Step-by-step explanation:

fudge it tgyshhvt8 to t up 7

3 0
3 years ago
Read 2 more answers
80 dollars for 16 tickets written as a unit rate, what is it?
shepuryov [24]

Answer:

5 dollars a ticket. Divide 80/16 to get tour answer.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the sum of a finite geometric sequence from n=1 to n=8, using the expression -2(3)^n-1
MissTica
\bf \qquad \qquad \textit{sum of a finite geometric sequence}&#10;\\\\&#10;S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}&#10;\end{cases}&#10;\\\\\\&#10;\sum\limits_{n=1}^{8}~-2(3)^{n-1}~~&#10;\begin{cases}&#10;n=8\\&#10;a_1=-2\\&#10;r=3&#10;\end{cases}\implies S_8=-2\left( \cfrac{1-3^8}{1-3} \right)&#10;\\\\\\&#10;S_8=\underline{-2}\left( \cfrac{1-6561}{\underline{-2}} \right)\implies s_8=1-6561\implies S_8=-6560
8 0
4 years ago
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