5c plus 9c is 14c bc 5 plus 9 is 14 and the exponent is c so 14c
Answer:
200 feet of the ground at a thirty degrees angle does not make a difference .
u need to know whether it is the top or bottom of it, the kite
I'm pretty sure that it is C. 12
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Length of the base = 16 km.
Length of the hypotenuse = 34 km. 
✎ The length of the missing leg ''
".
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The length of the missing leg "a" is
.
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Using Pythagoras theorem, we have


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
Hence verified. ✔

Answer:
y^3/(27 x^3)
Step-by-step explanation:
Simplify the following:
((3 x)/y)^(-3)
((3 x)/y)^(-3) = (y/(3 x))^3:
(y/(3 x))^3
Multiply each exponent in y/(3 x) by 3:
(y^3)/((3 x)^3)
Multiply each exponent in 3 x by 3:
y^3/(3^3 x^3)
3^3 = 3×3^2:
y^3/(3×3^2 x^3)
3^2 = 9:
y^3/(3×9 x^3)
3×9 = 27:
Answer: y^3/(27 x^3)