“<u>Aluminum</u>” and “<u>Nitrogen</u>” form an ionic bond.
Option: D
<u>Explanation</u>:
Aluminum and nitrogen are most likely to form an “ionic bond” among given pairs of elements in form of aluminum nitride. AlN is partially covalent and also show ionic characteristics as N needs 3 electrons to fill outer shell and Al has 3 electrons in valence shell. Hence
is cation and
is anion and have “electrostatic force” of attraction between these oppositely charged ions. Here ionic behavior is seen as nitrogen is more “electronegative” hence attract the shared pair of electrons which is earlier responsible for partial covalent bond formation.
Answer:
No
Explanation:
The gas will have more volume compared to the liquid.
Gases have no definite shape and no volume. They simply assume the shape of any container they are placed into. They will fill up the entirety of the bottle they are placed into.
Liquids have fixed volume although they do not have fixed shape. As they are held with weak intermolecular interactions, they are limited in space.
Therefore, they will maintain that initial volume at which they were introduced into the container.
- Liquids generally have a fixed volume and gases do not.
Answer:
d = 1.8 × 10⁻⁴ kg/L
Explanation:
Given data:
Moles of helium = 2 mol
Temperature and pressure = standard
Density = ?
Solution:
PV = nRT
V = nRT/ P
V = 2 mol × 0.0821 atm. L/ mol. K × 273 K / 1 atm
V = 44.8 L
Mass of helium:
Mass = number of moles × molar mass
Mass = 2 mol × 4 g/mol
Mass = 8 g
Mass = 0.008 kg
Density;
Density = mass/ volume
d = 0.008 kg/ 44.8 L
d = 1.8 × 10⁻⁴ kg/L
Answer:
Transition metals and lanthanide metals
Explanation:
Alkali metals, alkaline earth metals, halogens, and noble gases are all part of the main group elements.
Periods and families simply refer to the rows and columns of the periodic table. They don't specify the type of element.
Balanced chemical reaction: 2S + 3O₂ → 2SO₃.
1) Answer is: oxygen is limiting reactant.
n(S) = 3 mol; amount of sulfur.
n(O₂) = 4 mol; amount of oxygen.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
3 mol : n(O₂) = 2 : 3.
n(O₂) = (3 · 3 mol) ÷ 2.
n(O₂) = 4.5 mol; limiting reactant, because there is only 4 mol of oxygen.
2) Answer is: sulfur(S) is limiting reactant.
n(S) = 3 mol.
n(O₂) = 5 mol.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
n(S) : 5 mol = 2 : 3.
n(S) = 10 mol ÷ 3.
n(S) = 3.33 mol; there is only 3 mol of sulfur, so it is not enough.
3) Answer is: oxygen (O₂) is limiting reactant.
n(S) = 3 mol.
n(O₂) = 3 mol.
From balanced chemical reaction: n(S) : n(O₂) = 2 : 3.
3 mol : n(O₂) = 2 : 3.
n(O₂) = (3 · 3 mol) ÷ 2.
n(O₂) = 4.5 mol; limiting reactant, because there is only 3 mol of oxygen.