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FromTheMoon [43]
2 years ago
14

The main group elements exclude which parts of the periodic table?*

Chemistry
1 answer:
Elden [556K]2 years ago
7 0

Answer:

Transition metals and lanthanide metals

Explanation:

Alkali metals, alkaline earth metals, halogens, and noble gases are all part of the main group elements.

Periods and families simply refer to the rows and columns of the periodic table.  They don't specify the type of element.

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A compound contains potassium, nitrogen, and oxygen. the experimental analysis gave values of 45.942 % potassium and 16.458 % ni
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It should be KNO3 to the best of my understanding
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. Which groups are identical in all amino acids? (Points : 1)
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The answer is

<span>
only carboxyl groups (=C=OO-</span>
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If 5 moles of P4 reacted with 22 moles Cl2 according to the above reaction, determine:
GaryK [48]

Solution:

P_4+6Cl_2\rightarrow 4PCl_3

a) By stoichoimetry If 6 moles of Cl_2 gives 4 mole of PCl_3 , then 22 moles of Cl_2 will give: \frac{4}{6}\times 22=\frac{44}{3}=14.66 moles of PCl_3

b) If 6 moles of Cl_2 reacts with one mole of P_4 , then 22 moles of Cl_2 will react : \frac{1}{6}\times 22=\frac{11}{3}=3.66 moles of P_4

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7 0
3 years ago
Suppose 180 ml of 3.52x10^-4 M NaOH is mixed with 220 mL of 2.47x10^-4 M MgCl2.
velikii [3]
When in water, MgCl2 dissociates into magnesium ions and Cl- ions and NaOH into Na and OH ions. The equation is as follows:

MgCl2 = Mg2+ + 2Cl-
NaOH = Na+ + OH-

The initial concentrations are as follows:

[Mg2+] = .220(<span> 2.47x10^-4) / .220+.180 = 1.36x10^-4 M Mg2+
</span>[OH-] = .180 (3.52x10^-4) / .220+.180 = 1.58x10^-4 M OH-
6 0
3 years ago
Many hospitals, and some doctors\' offices, use radioisotopes for diagnosis and treatment, or in palliative care (relief of symp
Phantasy [73]

Answer:

a) ^{131}_{53} I

b) ^{192}_{77} Ir

c) ^{153}_{62} Sm

Explanation:

The symbols of the isotopes are written like

^{A}_{Z} X

where,

X is the element

A is the mass number (protons + neutrons)

Z is the atomic number (protons)

<em>a) Iodine-131</em>

The atomic number of iodine is 53. The mass number of this isotope is 131. The symbol is ^{131}_{53} I.

<em>b) Iridium-192</em>

The atomic number of iridium is 77. The mass number of this isotope is 192. The symbol is ^{192}_{77} Ir.

<em>c) Samarium-153</em>

The atomic number of samarium is 62. The mass number of this isotope is 153. The symbol is ^{153}_{62} Sm.

8 0
2 years ago
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