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4 years ago

0.1325 to the nearest tenth 0.0091 to the nearest thousandth 0.0196 to the nearest hundredth

2 answers:

8 0

0.1325 to the nerest tenth is 0.1, 0.0091 to the nearest thousandth is 0.009, and 0.0196 to the nearest hundreths is 0.02

Marianna [84]4 years ago

6 0

1.) 0.1
2.) 0.009
3.) 0.02

hope this helps

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A men’s softball league is experimenting with a yellow baseball that is easier to see during night games. One way to judge the e

vodomira [7]

Answer:

Yes. There is enough evidence to support the claim that there are fewer errors on average when the yellow ball is used.

Step-by-step explanation:

The question is incomplete:

The sample data is:

Yellow 5 2 6 7 2 5 3 8 4 9

White 7 6 8 5 9 11 8 3 6 10

This is a hypothesis test for the difference between populations means.

The claim is that there are fewer errors on average when the yellow ball is used.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0$

The significance level is α=0.05.

The sample 1 (yellow ball errors), of size n1=10 has a mean of 5.1 and a standard deviation of 2.42.

The sample 2 (white balls errors), of size n2=10 has a mean of 7.3 and a standard deviation of 2.41.

The difference between sample means is Md=-2.2.

$M_d=M_1-M_2=5.1-7.3=-2.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{2.42^2+2.41^2}{10}}\\\\\\s_{M_d}=\sqrt{\dfrac{11.665}{10}}=\sqrt{1.166}=1.08$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-2.2-0}{1.08}=\dfrac{-2.2}{1.08}=-2.037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=10+10-2=18$

This test is a left-tailed test, with 18 degrees of freedom and t=-2.037, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.028) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that there are fewer errors on average when the yellow ball is used.

3 0

4 years ago

Please need the answer

zvonat [6]

Answer:

A. True

B. True

C. False

Step-by-step explanation:

Hope that helps!

3 0

3 years ago

What is the length of BC?

Marat540 [252]

Answer:

x = 22, The length of BC is 22

Step-by-step explanation:

It is shown that angle ACB and angle ABC are congruent (The measure of angles are the same) in the picture. Since the angles are congruent, we can say that AC = AB because of base angle theorem converse. We can then substitute the given numbers in for AC and AB. We would then get 2x - 24 = x - 2. If you solve, you would get that x = 22 (The length of BC is 22).

7 0

3 years ago

Compute the range for the set of data. 10, 10, 10, 18, 29, 29, 29

nekit [7.7K]

Step-by-step explanation:

Range 29 - 10 = 19

the difference

4 0

3 years ago

A company offers a raffle whose grand prize is a $35,000 new car. Additional prizes are a $1,100 television and $600 computer. T

anastassius [24]

Answer:

-$ 10.13

Step-by-step explanation:

Given,

The cost price of each ticket = $ 22,

So, the value of each ticket other than price ticket = - $ 22, ( negative sign shows loss,i.e. if we don't get the price we will have the loss of $ 22 )

Now, there are 3 tickets in which first is of $35,000 price, second is of $1,100 and third is of $ 600,

So, the value of first ticket = 35000 - 22 = $ 34978,

Value of second ticket = 1100 - 22 = $ 1078,

Value of third ticket = 600 - 22 = $ 578,

Also,

$\text{Probability}=\frac{\text{Favourable outcome}}{\text{Total outcome}}$

Hence, by the above information we can make a table for the given situation,

Number 2997 1 1 1

Price -$ 22 $ 34978 $ 1078 $ 578

Probability 2997/3000 1/3000 1/3000 1/3000

Therefore, the expected value of a ticket

$=-22\times \frac{2997}{3000}+34978\times \frac{1}{3000}+578\times \frac{1}{3000}$

$=-$10.126$

≈ - $ 10.13

5 0

3 years ago