2 years ago

Find the area of a triangle that has a base of 16 inches and a height of 5 inches.

1 answer:

6 0

You’d do 16x5 and that would give you 80in^2 your welcome! Hope this helps!

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Kay [80]

From least to greatest
0.10, 0.1, 0.29, 5.07, 5.6

I hope this is what you were looking for....

8 0

3 years ago

Harlamova29_29 [7]

Answer:

5 $\frac{7}{8}$

Step-by-step explanation:

You subtract all those distances from 22 to calculate the remaining distance.

22-4 $\frac{3}{4}$ = 17 $\frac{1}{4}$

17 $\frac{1}{4}$ -5 $\frac{1}{8}$ =12 $\frac{1}{8}$

12 $\frac{1}{8}$ -0=12 $\frac{1}{8}$

12 $\frac{1}{8}$ -6 $\frac{1}{4}$ =5 $\frac{7}{8}$

So the answer is 5 $\frac{7}{8}$

(Yes I did these in my head)

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3 years ago

Novay_Z [31]

sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]

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2 years ago

Nesterboy [21]

Just convert the kilometers

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2 years ago

alexandr1967 [171]

Take a photo of it and then put the photo in Photo math

7 0

2 years ago