4 years ago

Someone please help out?

Mathematics

1 answer:

Delvig [45]4 years ago

7 0

I dont know im trying to figure that out

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It will be -12° tonight. The weatherman predicts by noon tomorrow. What will the temperature be by noon tomorrow?

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It will be 13° by noon.
-12°+25°=13°

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3 years ago

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3 years ago

Paula bought a jacket on sale for $6 less than half its original price. She paid $36 for the jacket. What was the original price

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Answer:

The correct answer is $30

Step-by-step explanation:

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4 years ago

Last one for real this time!<br> Find the perimeter and area the figure.

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Area = 1080

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I hope this helped <3

5 0

3 years ago

How do i solve for x? *you have to show work*

eduard

1) Factor the equation first:

$2e^{2x} + 4xe^{2x} = 0$
$e^{2x}(2 + 4x) = 0$

So either $e^{2x} = 0$ or $2 + 4x = 0$ . But $e^{2x} = 0$ can never equal 0! So, we only need to solve for the second equation:

$2 + 4x = 0$
$\bf x = {-\frac{1}{2}}$

2) First, single out the term with the exponent:

$2 + 3(4^{2x - 1}) = 43$
$3(4^{2x - 1}) = 41$
$4^{2x - 1} = \frac{41}{3}$

Now, taking the log base 4 of each side gives us

$2x - 1 = \log_4 \frac{41}{3}$

and we can now solve for x:

$2x - 1 = \log_4 \frac{41}{3}$
$2x = 1 + \log_4 \frac{41}{3}$
$2x = \log_4 4 + \log_4 \frac{41}{3}$
$2x = \log_4 \frac{164}{3}$
$x = \frac{1}{2} \log_4 \frac{164}{3}$
$x = \log_4 \sqrt \frac{164}{3}$
$\bf x = \log_4 2 \sqrt \frac{41}{3}$

8 0

3 years ago