Y=2(151)+3
y=302+3
y=305
So the 151st term is 305
3.0 NOT SURE IF ITS CORRECT
The answer is [ ∠A ≅ ∠A; A F/AB = AG/AC = 3 ]
Both triangles are the same just different sizes.
The length of A F is 9 units. The length of AB is 3 units.
To find the scale factor, just divide.
9 / 3 = 3
The length of AG is 6 units. The length of AC is 2 units.
To find the scale factor, just divide.
6 / 2 = 3
The only logical answer is B because the ratio's are written to where when you solve them, you get the scale factor 3.
Best of Luck!
It's an arithmetic progression with first term = 8 and common difference d =2:
so the next term is 14 + 2 = 16
